更新时间:2022-10-14 18:22:58
静态初始化数组的语法使用大括号,就像这样:
int数组[10] = {0};
这将零初始化数组。
有关多维数组,你需要嵌套的花括号,就像这样:
INT密码[ARRAY_SIZE] [ARRAY_SIZE] = {{0}};
注意 ARRAY_SIZE
必须是一个编译时常为这个工作。如果 ARRAY_SIZE
不是在编译时知道的,您必须使用动态初始化。 (preferably,一个的std ::矢量
)。
I am getting the following C++ error:
array must be initialized with a brace enclosed initializer
From this line of C++
int cipher[Array_size][Array_size];
What is the problem here? What does the error mean? Below is the full code:
string decryption(string todecrypt)
{
int cipher[Array_size][Array_size] = 0;
string ciphercode = todecrypt.substr(0,3);
todecrypt.erase(0,3);
decodecipher(ciphercode,cipher);
string decrypted = "";
while(todecrypt.length()>0)
{
string unit_decrypt = todecrypt.substr(0,Array_size);
todecrypt.erase(0,Array_size);
int tomultiply[Array_size]=0;
for(int i = 0; i < Array_size; i++)
{
tomultiply[i] = int(unit_encrypt.substr(0,1));
unit_encrypt.erase(0,1);
}
for(int i = 0; i < Array_size; i++)
{
int resultchar = 0;
for(int j = 0; j<Array_size; j++)
{
resultchar += tomultiply[j]*cipher[i][j];
}
decrypted += char((resultchar%229)-26);
}
}
return decrypted;
}
The syntax to statically initialize an array uses curly braces, like this:
int array[10] = { 0 };
This will zero-initialize the array.
For multi-dimensional arrays, you need nested curly braces, like this:
int cipher[Array_size][Array_size]= { { 0 } };
Note that Array_size
must be a compile-time constant for this to work. If Array_size
is not known at compile-time, you must use dynamic initialization. (Preferably, an std::vector
).