您可以定义路由定义以获取类似seo的网址

You can define a route definition to get seo friendly urls like that

这是使用属性路由的方法

Here is how you do it with attribute routing

public class ProfileController : Controller
{
    [Route("Profile/{userId}")]
    public ActionResult Index(string userId)
    {
        return Content("Proile for " + userId);
    }
}

因此，当用户访问/yourSite/profile/scott 时，将执行Profile控制器的Index操作，并且该操作的userId参数中将提供来自url(scott)的用户名值方法.在这里，我只是返回一个字符串"scott的配置文件".但是您可以对其进行查询以查询数据库以获得相应的记录，然后使用视图模型将该信息传递给视图.

So when you user access /yourSite/profile/scott the Index action of Profile controller will be executed and the username value from the url (scott) will be available in the userId parameter of the action method. Here i am simply returning a string "Profile for scott". But you can udpate it to query your database to get the corresponding record and pass that information to a view using a view model.

如果使用的是Razor页面，则将创建一个Profile页面及其模型并指定路线

If you are using Razor pages, you will create a Profile page and it's model and specify the route

@page "{id:int}"
@model ProfileModel
@{
    ViewData["Title"] = "Profile";
}    
<h3>@Model.Message</h3>

并在您的 Profile.cshtml.cs

public class ProfileModel : PageModel
{
    public string Message { get; set; }

    public void OnGet(string id)
    {
        Message = "Profile of "+ id;
    }
}

就像我上面提到的，我只是打印一个带有URL中传递的用户名的字符串.但是您可以更改它，以从db表中获取数据.

Like i mentioned above, i am just printing a string with the passed username from the url. But you can change it to get your data from your db table.