更新时间:1970-01-01 07:56:48
而不是让Jenkins成为一个代码(!BC12),你现在必须解析它,一个合适的字段并添加一个非运算符作为单独的字段列。
然后在你的LINQ中你可以说:
Instead of making Jenkins a "code" (!BC12), which you now have to parse, make it a proper "field" and add a "not" operator as a separate field column.
Then in your LINQ you can say:
.Where( x =>
(x.Jenkins != z.Jenkins && z.NotJenkins) ||
(x.Jenkins == z.Jenkins && !z.NotJenkins)
etc.
(或者有一个单独的排除列表用于查找)。
(Or have a separate "exclusion list" for lookups).