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t-sql 获取 2 个日期之间的所有日期

更新时间:1970-01-01 07:58:30

假设 SQL Server 2005+,使用递归查询:

WITH sample AS (
  SELECT CAST('2010-12-01' AS DATETIME) AS dt
  UNION ALL
  SELECT DATEADD(dd, 1, dt)
    FROM sample s
   WHERE DATEADD(dd, 1, dt) <= CAST('2010-12-04' AS DATETIME))
SELECT * 
  FROM sample

返回:

 dt
 ---------
 2010-12-01 00:00:00.000
 2010-12-02 00:00:00.000
 2010-12-03 00:00:00.000
 2010-12-04 00:00:00.000

使用 CAST/CONVERT 以随意格式化.>

使用参数启动&结束:

INSERT INTO dbo.YOUR_TABLE
  (datetime_column)
WITH sample AS (
    SELECT @start_date AS dt
    UNION ALL
    SELECT DATEADD(dd, 1, dt)
      FROM sample s
     WHERE DATEADD(dd, 1, dt) <= @end_date)
SELECT s.dt
  FROM sample s