分享程序员开发的那些事...
更新时间：2023-11-06 18:42:46
double tempo = Double.parseDouble（z）;
为什么要解析你的 尝试使用 i have a String x = "1086073200000" . This is basically millisecond which I need to convert to a Date. To convert i am using The problem is when i convert the string x to long , some digits go away due to the limit on the size of long. How do I preserve the entire String. THanks. / code> c $ c> $ c> c $ c $？ b Long.parseLong ：
DateFormat formatter = new SimpleDateFormat（dd / MM / yyyy）;
long milliSeconds = Long.parseLong（x）;
System.out.println（milliSeconds）;
日历calendar = Calendar.getInstance（）;
calendar.setTimeInMillis（milliSeconds）;
System.out.println（formatter.format（calendar.getTime（）））; DateFormat formatter = new SimpleDateFormat("dd/MM/yyyy");
long tempo1=Long.parseLong(x);
System.out.println(tempo1); // output is 86073200000 instead of the whole thing
long milliSeconds=1346482800000L;
Calendar calendar = Calendar.getInstance();
calendar.setTimeInMillis(milliSeconds);
System.out.println(formatter.format(calendar.getTime()));
double tempo=Double.parseDouble(z);
Why are you parsing your String which is supposed to be a Long as a Double?
Try using Long.parseLong:
String x = "1086073200000"
DateFormat formatter = new SimpleDateFormat("dd/MM/yyyy");
long milliSeconds= Long.parseLong(x);
System.out.println(milliSeconds);
Calendar calendar = Calendar.getInstance();
calendar.setTimeInMillis(milliSeconds);
System.out.println(formatter.format(calendar.getTime()));