您已经有了一个可行的想法，但 #flatten 是放错了地方！ - 它平坦的接收器，所以你可以用它来打开 [1，2，['富'，'酒吧']] 到 [1， 2，'富'，'酒吧'] 。

我忘了，无疑一些方法，但你可以连击

  a1.concat A2
A1 + A2＃创建新的数组一样，A1 + A2 =
 

或 prePEND /追加

  a1.push（* A2）＃注意星号
a2.unshift（* A1）＃注意星号，而A2是接收器
 

或拼接

  A1 [a1.length，0] = A2
A1 [a1.length..0] = A2
a1.insert（a1.length，* A2）
 

或添加和扁平

 （A1中;＆LT; A2）.flatten！ ＃调用#flatten而是会返回一个新的数组
 

somearray = ["some", "thing"]

anotherarray = ["another", "thing"]

somearray.push(anotherarray.flatten!)

I expected

["some","thing","another","thing"]

You've got a workable idea, but the #flatten! is in the wrong place -- it flattens its receiver, so you could use it to turn [1, 2, ['foo', 'bar']] into [1,2,'foo','bar'].

I'm doubtless forgetting some approaches, but you can concatenate:

a1.concat a2
a1 + a2              # creates a new array, as does a1 += a2

or prepend/append:

a1.push(*a2)         # note the asterisk
a2.unshift(*a1)      # note the asterisk, and that a2 is the receiver

or splice:

a1[a1.length, 0] = a2
a1[a1.length..0] = a2
a1.insert(a1.length, *a2)

or append and flatten:

(a1 << a2).flatten!  # a call to #flatten instead would return a new array