且构网

分享程序员开发的那些事...
且构网 - 分享程序员编程开发的那些事

Ajax模式弹出扩展器

更新时间:2023-10-19 20:37:28

嗨阿贾伊,

当您单击按钮或链接按钮控件时,服务器代码正在执行,对!!!然后只需检查按钮控件的位置应该与链接按钮相同即可.

希望对您有帮助.
hi ajay,

when u click button or link button control, server code is executing, right!!! then just check the location of button control is should be same as link button.

hope this will help you.


再说一次,如果发回邮件,您应该再次撤消Modalpopup.show()方法....这将帮助您...:)
Ajay if post back happens u should again revoke the Modalpopup.show() method....this will helps you...:)