更新时间:2023-11-05 11:13:04
你可以这样做以获得更好的性能:
You can do like this for beter performance:
public int getDuplicateCount(Integer[] arr){
int count = 0;
Set<Integer> set = new HashSet<Integer>();
for (int i = 0; i < arr.length; i++) {
if (set.contains(arr[i]))
count++;
set.add(arr[i]);
}
return count;
}