更新时间:2023-11-10 09:10:16
或者:
有没有办法参考最后一个列表的元素,使用
作为简写:
ref:=& lst [len(lst) - 1]#我知道语法是错了,但你得到了
的想法
然后使用列表的最后一个元素(假设元素是
a dict):
ref [" foo"] = 42
ref [" bar"] =" Ni!"
等
/ David
Aloha,
pi************@gmail.com 写道:不是比
更简单的方法[len(lst) - 1] = ...
lst [ -1] = ...
祝你节日快乐
LOBI
uote>我知道有一个简单的方法:)
只是为了满足我的好奇心:有没有办法做一些像
我在上面建议的参考解决方案?
Isn''t there an easier way than
lst[len(lst) - 1] = ...
?Or alternatively:
Is there a way to make reference to the last element of a list, to use
as a shorthand:
ref := &lst[len(lst) - 1] # I know syntax is wrong, but you get the
idea
and then using the last element of the list by (assuming the element is
a dict):
ref["foo"] = 42
ref["bar"] = "Ni!"
etc.
/David
Aloha,
pi************@gmail.com wrote:Isn''t there an easier way than
lst[len(lst) - 1] = ...
lst[-1] = ...
Wishing a happy day
LOBI
I knew there was an easy way :)
Just to satisfy my curiousity: Is there a way to do something like the
reference solution I suggest above?