我会这样做：

 XPathDocument doc = new XPathDocument（" input.xml"）; 
 XPathNavigator nav = doc.CreateNavigator（）; 
 XmlNamespaceManager mgr = new XmlNamespaceManager（nav.NameTable）; 
 mgr.AddNamespace（" g"，" http://base.google.com/ns/1.0"）; 

 foreach（doc.CreateNavigator（）中的XPathNavigator项。选择（&rss / channel / item"））
 {
 foreach（项目中的XPathNavigator链接。选择（"） ; g：image_link"，mgr））
 {
 Console.WriteLine（link.Value）; 
} 
} 

I am using XPathDocument to read xml.  XML Document format is given below. You can see that there are two similar elements with name of <g:image_link> ...how can i read identical elements?my current code only gets first image_link not second one. snippet of my program along with xml is given below

/////////////////////Main code/////////////////////////////

        static private XPathDocument _doc;
        static private XPathNavigator _nav;
        static private XPathNavigator nav2;
        static private XPathNodeIterator iterator;
        static private RssXmlReader rssXmlReader;

         _doc = new XPathDocument(_rssReaderUri);
         _nav = _doc.CreateNavigator();

            XPathExpression expr;
            expr = _nav.Compile("/rss/channel/item");
            iterator = _nav.Select(expr);

            try
            {
                while (iterator.MoveNext())
                {                    
                    nav2 = iterator.Current.Clone();
                    string gns = nav2.LookupNamespace("g");
                    string cns = nav2.LookupNamespace("c");

                    RssItemData temp = new RssItemData();

                     temp.Image_Link = "image_link@" + gns;

                 }

////////// RssItemData  class snippet.//////////////////

            private string _imageLink;
            public string Image_Link
            {
                get { return _imageLink; }
                set { _imageLink = RssXmlReader.getItemAttribute(value); }
            }

//////////////////////getItemAttribute//////////////////////

        internal static string getItemAttribute(string attributeName)
        {
            bool bChildFound = false;
            string[] str = attributeName.Split('@');
            if (str.Length > 1)
            {
                bChildFound = nav2.MoveToChild(str[0], str[1]);                
            }
            else
            {
                bChildFound = nav2.MoveToChild(attributeName, "");
            }

            if (bChildFound)
            {
                string attribVal = nav2.Value;
                nav2.MoveToParent();
                return attribVal;
            }

            return "";
        }

///////////XML///////////////////////////

- <rss version="2.0" xmlns:g="http://base.google.com/ns/1.0" xmlns:c="http://base.google.com/cns/1.0">
- <channel>
  <title>Website RSS</title>
  <description>Rss from testing company</description>
- <item>
   <g:image_link>http://testingcompany/Photos/793_1623.jpg</g:image_link>
   <g:image_link>http://testingcompany/Photos/793_1622.jpg</g:image_link>
  </item>
</channel>
</rss>  

I would simply do it like this:

            XPathDocument doc = new XPathDocument("input.xml");
            XPathNavigator nav = doc.CreateNavigator();
            XmlNamespaceManager mgr = new XmlNamespaceManager(nav.NameTable);
            mgr.AddNamespace("g", "http://base.google.com/ns/1.0");

            foreach (XPathNavigator item in doc.CreateNavigator().Select("rss/channel/item"))
            {
                foreach (XPathNavigator link in item.Select("g:image_link", mgr))
                {
                    Console.WriteLine(link.Value);
                }
            }