根据您的用例，您可以使用 FutureBuilder，或者你保持简单，创​​建一个变量来处理逻辑:

Depending on your usecase you can either use a FutureBuilder, or you keep it simple and create a variable to deal with the logic:

在您的小部件内部:

bool isLiked = false;

从 initState() 中调用您的函数:

Call your function from within initState():

@override
void initState() {
    super.initState();
    checkIfLikedOrNot();
}

改变你的逻辑来修改你的变量并告诉 Flutter 重新渲染:

Change your logic to modify your variable and tell Flutter to rerender:

    checkIfLikedOrNot() async{
       DocumentSnapshot ds = await reference.collection("likes").document(currentUser.uid).get();
        this.setState(() {
          isLiked = ds.exists;
        });

    }

画出对应的Icon:

Icon(isLiked?Icons.favorite:FontAwesomeIcons.heart,
     color: isLiked?Colors.red:null)

由于您显然正在处理值列表，因此将它们封装在 Object 中或使用 FutureBuilder 是有意义的.

Since you are apparently dealing with a list of values, it makes sense to encapsulate them in an Object or use the FutureBuilder.