更新时间:2023-11-29 16:22:52
您会希望在信息模式看
的意见
虽然它并不完整,因为它应该是。这是你想要的最终查询:
Though it's not as complete as it should be. This is the final query you'd want:
SELECT
KCU1.CONSTRAINT_NAME AS 'FK_CONSTRAINT_NAME'
, KCU1.TABLE_NAME AS 'FK_TABLE_NAME'
, KCU1.COLUMN_NAME AS 'FK_COLUMN_NAME'
, KCU1.ORDINAL_POSITION AS 'FK_ORDINAL_POSITION'
, KCU2.CONSTRAINT_NAME AS 'UQ_CONSTRAINT_NAME'
, KCU2.TABLE_NAME AS 'UQ_TABLE_NAME'
, KCU2.COLUMN_NAME AS 'UQ_COLUMN_NAME'
, KCU2.ORDINAL_POSITION AS 'UQ_ORDINAL_POSITION'
FROM INFORMATION_SCHEMA.REFERENTIAL_CONSTRAINTS RC
JOIN INFORMATION_SCHEMA.KEY_COLUMN_USAGE KCU1
ON KCU1.CONSTRAINT_CATALOG = RC.CONSTRAINT_CATALOG
AND KCU1.CONSTRAINT_SCHEMA = RC.CONSTRAINT_SCHEMA
AND KCU1.CONSTRAINT_NAME = RC.CONSTRAINT_NAME
JOIN INFORMATION_SCHEMA.KEY_COLUMN_USAGE KCU2
ON KCU2.CONSTRAINT_CATALOG =
RC.UNIQUE_CONSTRAINT_CATALOG
AND KCU2.CONSTRAINT_SCHEMA =
RC.UNIQUE_CONSTRAINT_SCHEMA
AND KCU2.CONSTRAINT_NAME =
RC.UNIQUE_CONSTRAINT_NAME
AND KCU2.ORDINAL_POSITION = KCU1.ORDINAL_POSITION
在这里看到更多信息。
http://msdn.microsoft.com/ EN-US /库/ aa175805(v = sql.80)的.aspx