你需要一个 top_hits 聚合。 p>

根据您的具体情况：

  {
查询：{
multi_match：{
 ... 
} 
}，
aggs：{
top-uids 
条款：{
field：uid
}，
aggs：{
top_uids_hits：{
top_hits ：{
sort：[
 {
_score：{
order：de sc
} 
} 
]，
size：1 
} 
} 
} 
} 
} 
} 
 

上面的查询执行你的 multi_match 根据 uid 查询并聚合结果。对于每个uid bucket，它只返回一个结果，但是桶中的所有文档都是根据 _score 按照后代顺序排序的。

All my documents have a uid field with an ID that links the document to a user. There are multiple documents with the same uid.

I want to perform a search over all the documents returning only the highest scoring document per unique uid.

The query selecting the relevant documents is a simple multi_match query.

You need a top_hits aggregation.

And for your specific case:

{
  "query": {
    "multi_match": {
      ...
    }
  },
  "aggs": {
    "top-uids": {
      "terms": {
        "field": "uid"
      },
      "aggs": {
        "top_uids_hits": {
          "top_hits": {
            "sort": [
              {
                "_score": {
                  "order": "desc"
                }
              }
            ],
            "size": 1
          }
        }
      }
    }
  }
}

The query above does perform your multi_match query and aggregates the results based on uid. For each uid bucket it returns only one result, but after all the documents in the bucket were sorted based on _score in descendant order.