如果我正确理解，该文件将包含文字文本 \u65b9\u6cd5\uff0c\u5220\u9664＼ 5u5b58\u50a8\u5728 （所以它是纯ASCII码，但带有反斜杠，并且所有描述Unicode序号的方式都与在Python str $ c中一样$ c>文字）。如果是这样，有两种方法可以解决此问题：

If I understand correctly, the file contains the literal text \u65b9\u6cd5\uff0c\u5220\u9664\u5b58\u50a8\u5728 (so it's plain ASCII, but with backslashes and all that describe the Unicode ordinals the same way you would in a Python str literal). If so, there are two ways to handle this:

1. 以二进制模式读取文件，然后调用 mystr = mybytes.decode（'unicode-escape'）从 bytes 转换为 str 解释转义


2. 以文本模式读取文件，并使用 codecs 模块进行文本->文本转换（字节现在，仅 codecs 模块功能支持字节到文本和文本到文本的编解码器； bytes.decode 仅用于字节文本和 str.encode 纯粹是文本到字节，因为通常在Py2中， str.encode 和 unicode.decode 是一个错误，删除危险的方法可以使您更容易理解转换的方向。 decodedstr = codecs.decode（encodedstr，'unicode-escape'）

1. Read the file in binary mode, then call mystr = mybytes.decode('unicode-escape') to convert from the bytes to str interpreting the escapes
2. Read the file in text mode, and use the codecs module for the "text -> text" conversion (bytes to bytes and text to text codecs are now supported only by the codecs module functions; bytes.decode is purely for bytes to text and str.encode is purely for text to bytes, because usually, in Py2, str.encode and unicode.decode was a mistake, and removing the dangerous methods makes it easier to understand what direction the conversions are supposed to go), e.g. decodedstr = codecs.decode(encodedstr, 'unicode-escape')