是这样的:

:%s/\([^=]*\)\s\+=\s\+\([^;]*\)/\2 = \1

如果您的代码比示例中显示的更复杂，您可能需要稍微处理一下.

You might have to fiddle with it a bit if you have more complex code than what you have shown in the example.

解释

我们使用 s/find/replace 命令.find 部分让我们知道:

We use the s/find/replace comand. The find part gets us this:

1. 由除等号以外的任何字符组成的最长字符串，用 [^=]* ...
表示
2. ... 后跟一个或多个空格，\s\+(+ 前面的额外的 \ 是 vim 的奇葩)
3. ... 后跟 = 和任意数量的空格，=\s\+
4. ... 后跟尽可能长的非分号字符串，[^;]*

1. longest possible string consisting of anything-but-equal-signs, expressed by [^=]* ...
2. ... followed by one or more spaces, \s\+ (the extra \ in front of + is a vim oddity)
3. ... followed by = and again any number of spaces, =\s\+
4. ... followed by the longest possible string of non-semicolon characters, [^;]*

然后我们放入几个捕获括号来保存我们需要构造替换字符串的内容，那就是 \(stuff\) 语法

Then we throw in a couple of capturing parentheses to save the stuff we'll need to construct the replacement string, that's the \(stuff\) syntax

最后，我们在 s/find/replace 部分使用捕获的字符串em>replace 命令:即 \1 和 \2.

And finally, we use the captured strings in the replace part of the s/find/replace command: that's \1 and \2.