:
公共表格1()
{
initializecomponent();
}

到

if you want to set location change:
public form1()
{
initializecomponent();
}

to

public form1( int x, int y)
{
 initializecomponent();
this.location=new point(x,y);
}

但是如果您想更改大小，只需更换:

this.location =新点(x，y);

与

this.size =新尺寸(x，y);

因此，当您呼叫打开表单时，请像这样:
form1 f1 =新form1(150,150);
f1.show();

but if you want to change the size just replace:

this.location=new point(x,y);

with

this.size=new size(x,y);

so when you call to open form call it like:
form1 f1=new form1(150,150);
f1.show();

到sanforjackass，

谢谢您的回复.
但是:
我没有仅适用于表单的属性位置form.locationchange-
活动吗?

您只了解一半的问题-我想根据显示的用户控件来设置Windows位置

谢谢

To sanforjackass,

Hi thanks for your reply.
But:
I dont have property location for my form only form.locationchange -
event?

U understood only half of the quesiton- i want to set the windows location acoording to a user control displayed

Thanks