更新时间:2022-12-26 21:47:54
简单的列表理解应该可以解决问题:
A simple list comprehension should do the trick:
>>> a = [{'key': 'value'} for _ in range(3)]
>>> a
[{'key': 'value'}, {'key': 'value'}, {'key': 'value'}]
>>> a[0]['key'] = 'poop'
>>> a
[{'key': 'poop'}, {'key': 'value'}, {'key': 'value'}]