通常，sed 中的量词是贪婪的，这就是为什么你总是匹配最后一个 =.定义第一个=的是它之前的所有字符都不是=，所以:

Normally, quantifiers in sed are greedy, which is why you will always match the last =. What defines the first = is that all the characters before it are not =, so:

sed 's/^[^=]*=//'

您的问题意味着 : 或 = 是有效标记，在这种情况下

Your question implies that either : or = are valid markers, in which case

sed 's/^[^=:]*[=:]//'