sed -n '/^START=A$/,/^END$/p' data

-n 选项表示默认不打印；然后脚本说'在包含 START=A 的行和下一个 END 之间打印.

The -n option means don't print by default; then the script says 'do print between the line containing START=A and the next END.

你也可以用 awk 来做到:

You can also do it with awk:

一个模式可以由两个以逗号分隔的模式组成；在这种情况下，该操作是为从第一个模式出现到第二个模式出现的所有行.

A pattern may consist of two patterns separated by a comma; in this case, the action is performed for all lines from an occurrence of the first pattern though an occurrence of the second.

(来自 Mac OS X 上的 man awk).

(from man awk on Mac OS X).

awk '/^START=A$/,/^END$/ { print }' data

给定问题中数据文件的修改形式:

Given a modified form of the data file in the question:

START=A
  xxx01
  xxx02
END
START=A
  xxx03
  xxx04
END
START=A
  xxx05
  xxx06
END
START=B
  xxx07
  xxx08
END
START=A
  xxx09
  xxx10
END
START=C
  xxx11
  xxx12
END
START=A
  xxx13
  xxx14
END
START=D
  xxx15
  xxx16
END

输出使用 GNU sed 或 Mac OS X (BSD) sed，并使用 GNU awk 或 BSD awk代码>，是一样的:

The output using GNU sed or Mac OS X (BSD) sed, and using GNU awk or BSD awk, is the same:

START=A
  xxx01
  xxx02
END
START=A
  xxx03
  xxx04
END
START=A
  xxx05
  xxx06
END
START=A
  xxx09
  xxx10
END
START=A
  xxx13
  xxx14
END

请注意我是如何修改数据文件的，以便更容易查看打印的各个数据块在文件中的来源.

Note how I modified the data file so it is easier to see where the various blocks of data printed came from in the file.

如果您有不同的输出要求(例如仅 START=A 和 END 之间的第一个块"，或仅最后一个...")，那么您需要在问题中更清楚地阐明这一点.

If you have a different output requirement (such as 'only the first block between START=A and END', or 'only the last ...'), then you need to articulate that more clearly in the question.