这绝对是可能的.您只需要为 viewpager 使用子片段.除此之外，实现很简单.创建自定义寻呼机适配器，使用标准的 viewpager api

This is definitely possible. You just need to use child fragments for the viewpager. Other than that the implementation is straightforward. Create a custom pager adapter, use the standard viewpager api

像这样扩展 FragmentPagerAdapter:

Extend FragmentPagerAdapter like so:

private class MyPagerAdapter extends FragmentPagerAdapter
{
    public MyPagerAdapter (FragmentManager fm) {
        super(fm);
    }

    @Override
    public Fragment getItem(int i) {
        switch (i) {
            case 0:
                return Fragment1;
            case 1:
                return Fragment2;

        }
    }

    @Override
    public int getCount() {
        return 2;
    }

    @Override
    public CharSequence getPageTitle(int position) {
        switch (position) {
            case 0:
                return FRAGMENT_1_NAME;
            case 1:
                return FRAGMENT_2_NAME;



        }
    }

当然，你需要一个带有 viewpager 的布局，然后确保在 Fragment A 中像这样连接它:

You'll need an layout with a viewpager of course, then just make sure to hook it up like this in Fragment A:

myPagerAdapter = new MyPagerAdapter(this.getChildFragmentManager());
myPager = (ViewPager) mRoot.findViewById(R.id.pager);
myPager.setAdapter(myPagerAdapter);

请注意，除非您的最低 SDK 为 4.2 或更高版本，否则您将需要使用支持库和支持片段，因为子片段是 API 17

Note that you'll need to use the support library and support fragments unless your minimum SDK is 4.2 or higher, since the child fragments are API 17