更新时间:2023-01-11 11:24:15
首先,您至少需要一个 URLStreamHandler.这实际上会打开到给定 URL 的连接.请注意,这被简单地称为Handler
;这允许您指定 java -Djava.protocol.handler.pkgs=org.my.protocols
并且它会自动被拾取,使用简单"包名称作为支持的协议(在这种情况下类路径").
First up, you're going to need at least a URLStreamHandler. This will actually open the connection to a given URL. Notice that this is simply called Handler
; this allows you to specify java -Djava.protocol.handler.pkgs=org.my.protocols
and it will automatically be picked up, using the "simple" package name as the supported protocol (in this case "classpath").
new URL("classpath:org/my/package/resource.extension").openConnection();
package org.my.protocols.classpath;
import java.io.IOException;
import java.net.URL;
import java.net.URLConnection;
import java.net.URLStreamHandler;
/** A {@link URLStreamHandler} that handles resources on the classpath. */
public class Handler extends URLStreamHandler {
/** The classloader to find resources from. */
private final ClassLoader classLoader;
public Handler() {
this.classLoader = getClass().getClassLoader();
}
public Handler(ClassLoader classLoader) {
this.classLoader = classLoader;
}
@Override
protected URLConnection openConnection(URL u) throws IOException {
final URL resourceUrl = classLoader.getResource(u.getPath());
return resourceUrl.openConnection();
}
}
如果你控制了代码,你就可以做到
If you control the code, you can do
new URL(null, "classpath:some/package/resource.extension", new org.my.protocols.classpath.Handler(ClassLoader.getSystemClassLoader()))
这将使用您的处理程序打开连接.
and this will use your handler to open the connection.
但同样,这并不令人满意,因为您不需要 URL 来执行此操作 - 您想要执行此操作是因为某些您无法(或不想)控制的库需要 url...
But again, this is less than satisfactory, as you don't need a URL to do this - you want to do this because some lib you can't (or don't want to) control wants urls...
最终的选择是注册一个 URLStreamHandlerFactory
来处理整个 jvm 的所有 url:
The ultimate option is to register a URLStreamHandlerFactory
that will handle all urls across the jvm:
package my.org.url;
import java.net.URLStreamHandler;
import java.net.URLStreamHandlerFactory;
import java.util.HashMap;
import java.util.Map;
class ConfigurableStreamHandlerFactory implements URLStreamHandlerFactory {
private final Map<String, URLStreamHandler> protocolHandlers;
public ConfigurableStreamHandlerFactory(String protocol, URLStreamHandler urlHandler) {
protocolHandlers = new HashMap<String, URLStreamHandler>();
addHandler(protocol, urlHandler);
}
public void addHandler(String protocol, URLStreamHandler urlHandler) {
protocolHandlers.put(protocol, urlHandler);
}
public URLStreamHandler createURLStreamHandler(String protocol) {
return protocolHandlers.get(protocol);
}
}
要注册处理程序,请使用您配置的工厂调用 URL.setURLStreamHandlerFactory()
.然后像第一个示例一样执行 new URL("classpath:org/my/package/resource.extension")
就可以了.
To register the handler, call URL.setURLStreamHandlerFactory()
with your configured factory. Then do new URL("classpath:org/my/package/resource.extension")
like the first example and away you go.
请注意,每个 JVM 只能调用此方法一次,并注意 Tomcat 将使用此方法注册 JNDI 处理程序 (AFAIK).尝试码头(我会);最坏的情况是,您可以先使用该方法,然后它必须在您身边工作!
Note that this method may only be called once per JVM, and note well that Tomcat will use this method to register a JNDI handler (AFAIK). Try Jetty (I will be); at worst, you can use the method first and then it has to work around you!
我将其发布到公共领域,并询问如果您想修改您在某处启动 OSS 项目并在此处评论详细信息.更好的实现是有一个 URLStreamHandlerFactory
,它使用 ThreadLocal
s 为每个 Thread.currentThread().getContextClassLoader 存储
.我什至会给你我的修改和测试类.URLStreamHandler
s()
I release this to the public domain, and ask that if you wish to modify that you start a OSS project somewhere and comment here with the details. A better implementation would be to have a URLStreamHandlerFactory
that uses ThreadLocal
s to store URLStreamHandler
s for each Thread.currentThread().getContextClassLoader()
. I'll even give you my modifications and test classes.