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分享程序员开发的那些事...
且构网 - 分享程序员编程开发的那些事

连续删除重复的单词

更新时间:2023-01-12 23:09:50

我认为这将作为您的最后一行:

I think this will work as your final line:

Table1$Col1 <- sapply(broken,function(x) paste(unique(x), collapse=','))

因为我是包functional的粉丝,所以这是等效的:

Because I am a fan of package functional, here is an equivalent:

sapply(broken, Compose(unique, Curry(paste, collapse=',')))