更新时间:2023-01-15 16:48:23
您可以使用.split("/")
并遍历结果,在嵌套对象中创建属性:
You could use .split("/")
and iterate over the results, creating properties in nested objects:
let paths = [
"path1/subpath1/file111.doc",
"path1/subpath1/file112.doc",
"path1/subpath2/file121.doc",
"path1/subpath2/file122.doc",
"path2/subpath1/file211.doc",
"path2/subpath1/file212.doc",
"path2/subpath2/file221.doc",
"path2/subpath2/file222.doc",
"path2/additionalpath3/additionalpath1/file2311.doc"
];
let treePath = {};
paths.forEach(path => {
let levels = path.split("/");
let file = levels.pop();
let prevLevel = treePath;
let prevProp = levels.shift();
levels.forEach(prop => {
prevLevel[prevProp] = prevLevel[prevProp] || {};
prevLevel = prevLevel[prevProp];
prevProp = prop;
});
prevLevel[prevProp] = (prevLevel[prevProp] || []).concat([file]);
});
console.log(treePath);
或者:
let paths = [
"path1/subpath1/file111.doc",
"path1/subpath1/file112.doc",
"path1/subpath2/file121.doc",
"path1/subpath2/file122.doc",
"path2/subpath1/file211.doc",
"path2/subpath1/file212.doc",
"path2/subpath2/file221.doc",
"path2/subpath2/file222.doc",
"path2/additionalpath3/additionalpath1/file2311.doc"
];
let treePath = {};
paths.forEach(path => {
let levels = path.split("/");
let file = levels.pop();
levels.reduce((prev, lvl, i) => {
return prev[lvl] = (levels.length - i - 1) ? prev[lvl] || {} : (prev[lvl] || []).concat([file]);
}, treePath);
});
console.log(treePath);