更新时间:2023-01-16 11:20:55
解决方案如下. JavaScriptSerializer从json字符串('json')创建对象('o'),然后BuildVariablesList方法遍历该对象并填充包含结果的字典('additionalParameters').
The solution for this is as following. JavaScriptSerializer creates object ('o') from json string ('json'), than method BuildVariablesList traverse the object and populates dictionary ('additionalParameters') that contains results.
var jss = new JavaScriptSerializer();
var o = return new DynamicJsonObject(jss.Deserialize<Dictionary<string, object>>(json));
var additionalParameters = new Dictionary<string, string>();
BuildVariablesList(o.GetInternalDictionary(), "", additionalParameters);
private static string AppendToPathString (string path, object part )
{
return path.Trim().Length == 0 ? part.ToString() : path + '.' + part;
}
public static void BuildVariablesList(object obj, string path, Dictionary<string, string> result)
{
if ( obj is ArrayList)
{
var arrayObj = obj as ArrayList;
for (var i = 0; i<arrayObj.Count; i++ )
{
BuildVariablesList(arrayObj[i], AppendToPathString(path,i), result);
}
}else if ( obj is Dictionary<string, object>)
{
var dictObject = obj as Dictionary<string, object>;
foreach (var entry in dictObject)
{
if (entry.Value is String && (path.Trim().Length > 0 || !ReservedFieldNames.Contains( entry.Key.ToLower())))
{
result.Add(AppendToPathString(path,entry.Key), entry.Value as String);
}
else if (entry.Value is Dictionary<string, object>)
{
BuildVariablesList(entry.Value as Dictionary<string, object>, AppendToPathString(path, entry.Key), result);
}
else if (entry.Value is ArrayList)
{
BuildVariablesList(entry.Value as ArrayList, AppendToPathString(path, entry.Key), result);
}
}
}
}