您应该意识到您的领域可能非常复杂，但在您提到的情况下，可以通过以下方式解决:

You should be aware that your field can be very complex but in the case you mentioned, can be resolved with this:

resolveField(data: any, field: string): any {
  if (data && field) {
    let fields: string[] = field.split('.');
    let value = data;
    for(let i = 0, len = fields.length; i < len; ++i) {
      if (value == null) {
        return null;
      } else {
        const pos: number = fields[i].match(/\d+/g)?.[0];
        if(pos != null) {
          const property = fields[i].match(/^\w+/g);
          value = value[property][pos];
        } else {
          value = value[fields[i]];
        }
      }
    }
    return value;
  } else {
    return null;
  }
}

您可以将 resolveField 函数用作逻辑的一部分.您可以根据需要或需要对其进行修改，例如:这里仅考虑将字母作为属性名称的一部分.

You can use the resolveField function as part of your logic. You can modify it, as you want or required, for example: here is considering only letters as part of the property names.

这是解决方案 用于您的代码.