更新时间:2023-01-16 18:15:18
相信你要找的功能是
strconv.ParseFloat()
查看示例这里
但是这个函数的返回类型是float64.
But return type of this function is float64.
如果您不需要作为字符串传递的数字的小数部分,那么下面的函数就可以完成这项工作:
If you don't need fractional part of the number passed as the string following function would do the job:
func StrToInt(str string) (int, error) {
nonFractionalPart := strings.Split(str, ".")
return strconv.Atoi(nonFractionalPart[0])
}