我相信这会给您您想要的东西.如果可能，您将不得不更改类的属性名称-

I believe this will give you what you want. You will have to change your class property names if possible -

        class MyClass
        {
             public string email_address { get; set; }
             public string status { get; set; }
        }

        List<MyClass> data = new List<MyClass>() { new MyClass() { email_address = "email1@email.com", status = "good2go" }, new MyClass() { email_address = "email2@email.com", status = "good2go" } };
        var json = JsonConvert.SerializeObject(new
        {
            operations = data
        });