更新时间:2023-01-17 16:12:55
最简单的方法可能是的扁平化问题,然后做GROUP BY:
The easiest way is probably to "flatten" the problem and then do the group by:
var query = officers.SelectMany(
x => new[] {
new { x.Name, RO = x.ReportingOfficer1 },
new { x.Name, RO = x.ReportingOfficer2 },
new { x.Name, RO = x.ReportingOfficer3 }
}
);
var grouped = query.GroupBy(y => y.RO);
foreach (var group in grouped) {
foreach (var item in group) {
Console.WriteLine(String.Format("{0}: {1}", item.RO, item.Name));
}
}
在这里,我假设人员
是的IEnumerable<官>
其中
class Officer {
public string Name { get; set; }
public string ReportingOfficer1 { get; set; }
public string ReportingOfficer2 { get; set; }
public string ReportingOfficer3 { get; set; }
}
使用您的样本数据,这是我的输出:
With your sample data this is my output:
John: A
John: B
Jack: A
Rob: A
Rob: C
Earl: B
Carl: B
Carl: D
Chris: C
Kenny: C
Rodney: D
Jacob: D