NumberRange *numberrange;
numberrange->NumberRange (5, 9);

这不是你如何构造一个新的 NumberRange 。您可以执行

This is not how you construct a new NumberRange. You can do either

NumberRange *numberrange = new NumberRange(5, 9);

或者更好地避免多余的内存分配：

Or better yet, avoid the superfluous memory allocation:

NumberRange numberrange(5, 9);