更新时间:2023-01-17 19:45:31
如果您正在使用 https://github.com/lukegothic/Newtonsoft.Json/blob/master/Src/Newtonsoft.Json/Converters /XmlNodeConverter.cs ,看来您需要这样做:
If you are using the variant version of XmlNodeConverter
described in this answer and available here: https://github.com/lukegothic/Newtonsoft.Json/blob/master/Src/Newtonsoft.Json/Converters/XmlNodeConverter.cs, it looks like you would need to do:
ele.SetAttribute("Type", "http://james.newtonking.com/projects/json", "Integer");
或者,对于双精度值:
ele.SetAttribute("Type", "http://james.newtonking.com/projects/json", "Float");
或者,您可以直接使用Linq-to-JSON手动将转换字符串值修改为数字值,例如:
Alternatively, you could use Linq-to-JSON out-of-the-box to manually modify convert string values to numeric values, for instance:
string xml = @"<fulfillment xmlns:json=""http://james.newtonking.com/projects/json""><tracking_number>937467375966</tracking_number><tracking_url>google.com/search?q=937467375966</tracking_url>; <line_items json:Array=""true""><id>759263947</id><quantity>1.00000</quantity></line_items></fulfillment>";
var doc = new XmlDocument();
doc.LoadXml(xml);
var obj = JObject.Parse(JsonConvert.SerializeXmlNode(doc));
foreach (var value in obj.Descendants().OfType<JValue>().Where(v => v.Type == JTokenType.String))
{
long lVal;
if (long.TryParse((string)value, out lVal))
{
value.Value = lVal;
continue;
}
double dVal;
if (double.TryParse((string)value, out dVal))
{
value.Value = dVal;
continue;
}
decimal dcVal;
if (decimal.TryParse((string)value, out dcVal))
{
value.Value = dcVal;
continue;
}
}
var json = obj.ToString();
Debug.WriteLine(json);