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分享程序员开发的那些事...
且构网 - 分享程序员编程开发的那些事

从Excel数据表来在C#中使用的Open XML

更新时间:2023-01-19 16:16:06

我想这应该做你在问什么。另一个功能是那里只是为了对付如果你有共同的字符串,我以为你在列标题做。不知道这是完美的,但我希望它能帮助。

I think this should do what you're asking. The other function is there just to deal with if you have shared strings, which I assume you do in your column headers. Not sure this is perfect, but I hope it helps.

static void Main(string[] args)
{
    DataTable dt = new DataTable();

    using (SpreadsheetDocument spreadSheetDocument = SpreadsheetDocument.Open(@"..\..\example.xlsx", false))
    {

        WorkbookPart workbookPart = spreadSheetDocument.WorkbookPart;
        IEnumerable<Sheet> sheets = spreadSheetDocument.WorkbookPart.Workbook.GetFirstChild<Sheets>().Elements<Sheet>();
        string relationshipId = sheets.First().Id.Value;
        WorksheetPart worksheetPart = (WorksheetPart)spreadSheetDocument.WorkbookPart.GetPartById(relationshipId);
        Worksheet workSheet = worksheetPart.Worksheet;
        SheetData sheetData = workSheet.GetFirstChild<SheetData>();
        IEnumerable<Row> rows = sheetData.Descendants<Row>();

        foreach (Cell cell in rows.ElementAt(0))
        {
            dt.Columns.Add(GetCellValue(spreadSheetDocument, cell));
        }

        foreach (Row row in rows) //this will also include your header row...
        {
            DataRow tempRow = dt.NewRow();

            for (int i = 0; i < row.Descendants<Cell>().Count(); i++)
            {
                tempRow[i] = GetCellValue(spreadSheetDocument, row.Descendants<Cell>().ElementAt(i-1));
            }

            dt.Rows.Add(tempRow);
        }

    }
    dt.Rows.RemoveAt(0); //...so i'm taking it out here.

}


public static string GetCellValue(SpreadsheetDocument document, Cell cell)
{
    SharedStringTablePart stringTablePart = document.WorkbookPart.SharedStringTablePart;
    string value = cell.CellValue.InnerXml;

    if (cell.DataType != null && cell.DataType.Value == CellValues.SharedString)
    {
        return stringTablePart.SharedStringTable.ChildElements[Int32.Parse(value)].InnerText;
    }
    else
    {
        return value;
    }
}