这没有什么复杂的，它与请求/响应结构没有任何关系.您需要做的就是将模板字符串传递给 django.template.Template 构造函数(顺便说一句，我已经更改了模型的名称，以避免混淆):

from django.template import Context, Template从 myapp.models 导入 DbTemplates = DbTemplate.objects.get(pk=123).contenttpl = 模板tpl.render(上下文(dict(a=123, b=456)))

Im trying to render a django template from a database outside of djangos normal request-response structure. But it appears to be non-trivial due to the way django templates are compiled. I want to do something like this:

>>> s = Template.objects.get(pk = 123).content
>>> some_method_to_render(s, {'a' : 123, 'b' : 456})
>>> ... the rendered output here ...

How do you do this?

There's nothing complicated about this, and it doesn't have anything to do with the request/response structure. All you need to do is pass the template string into the django.template.Template constructor (BTW, I've changed the name of your model, to avoid confusion):

from django.template import Context, Template
from myapp.models import DbTemplate

s = DbTemplate.objects.get(pk=123).content
tpl = Template(s)
tpl.render(Context(dict(a=123, b=456)))