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分享程序员开发的那些事...
且构网 - 分享程序员编程开发的那些事

得到一个图片从联系

更新时间:2023-01-19 17:59:37

也许这将帮助你(接触是通过的getId标识()):

  / **
 返回:照片URI
 * /
公共乌里getPhotoUri(){
    尝试 {
        光标CUR = this.ctx.getContentResolver()查询(
                ContactsContract.Data.CONTENT_URI,
                空值,
                ContactsContract.Data.CONTACT_ID +=+ this.getId()+和
                        + ContactsContract.Data.MIMETYPE +=
                        + ContactsContract.CommonDataKinds.Photo.CONTENT_ITEM_TYPE +',空,
                空值);
        如果(CUR!= NULL){
            如果(!cur.moveToFirst()){
                返回null; //没有照片
            }
        } 其他 {
            返回null; //在光标过程中的错误
        }
    }赶上(例外五){
        e.printStackTrace();
        返回null;
    }
    乌里人= ContentUris.withAppendedId(ContactsContract.Contacts.CONTENT_URI,龙
            .parseLong(的getId()));
    返回Uri.withAppendedPath(人,ContactsContract.Contacts.Photo.CONTENT_DIRECTORY);
}
 

用法是:

 开放的U = objItem.getPhotoUri();
如果(U!= NULL){
        mPhotoView.setImageURI(U);
} 其他 {
        mPhotoView.setImageResource(R.drawable.ic_contact_picture_2);
}
 

Alright, I'm just trying to learn about using Contact information, but I'm a bit stuck. I would like to be able to display a picture for the contact. Using the following code that I have, how would I be able to put the photo for the contact in the ImageView in contact_entry?

ListView contacts_list = (ListView) findViewById(R.id.contacts_list);

// Gets the URI of the db
Uri uri = ContactsContract.Contacts.CONTENT_URI;
// What to grab from the db
String[] projection = new String[] {
        ContactsContract.Contacts._ID,
        ContactsContract.Contacts.DISPLAY_NAME,
        ContactsContract.Contacts.PHOTO_ID
};

String sortOrder = ContactsContract.Contacts.DISPLAY_NAME + " COLLATE LOCALIZED ASC";

Cursor cursor = managedQuery(uri, projection, null, null, sortOrder);

String[] fields = new String[] {
        ContactsContract.Data.DISPLAY_NAME
};

int[] values = { 
        R.id.contactEntryText
};

SimpleCursorAdapter adapter = new SimpleCursorAdapter(this, R.layout.contact_entry, cursor,
        fields, values);
contacts_list.setAdapter(adapter);

contact_entry.xml

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout 
    xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="fill_parent"
    android:layout_height="54px">
    <ImageView
        android:id="@+id/contactPhoto"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content" 
        android:src="@drawable/ic_contact_picture_3"/>
    <TextView 
        android:text="@+id/contactEntryText"
        android:id="@+id/contactEntryText"
        android:layout_width="fill_parent"
        android:layout_height="wrap_content"/>
</LinearLayout>

Probably this will help you(contact is identified by getId()):

/**
 * @return the photo URI
 */
public Uri getPhotoUri() {
    try {
        Cursor cur = this.ctx.getContentResolver().query(
                ContactsContract.Data.CONTENT_URI,
                null,
                ContactsContract.Data.CONTACT_ID + "=" + this.getId() + " AND "
                        + ContactsContract.Data.MIMETYPE + "='"
                        + ContactsContract.CommonDataKinds.Photo.CONTENT_ITEM_TYPE + "'", null,
                null);
        if (cur != null) {
            if (!cur.moveToFirst()) {
                return null; // no photo
            }
        } else {
            return null; // error in cursor process
        }
    } catch (Exception e) {
        e.printStackTrace();
        return null;
    }
    Uri person = ContentUris.withAppendedId(ContactsContract.Contacts.CONTENT_URI, Long
            .parseLong(getId()));
    return Uri.withAppendedPath(person, ContactsContract.Contacts.Photo.CONTENT_DIRECTORY);
}

Usage is:

Uri u = objItem.getPhotoUri();
if (u != null) {
        mPhotoView.setImageURI(u);
} else {
        mPhotoView.setImageResource(R.drawable.ic_contact_picture_2);
}