你可能想利用 GROUP BY 子句而不是在那里使用 DISTINCT，即:

SELECT productId, Size,SUM(CASE WHEN storeID IN ('BCN', 'BCN2') THEN stock ELSE 0 END) AS stockBCN,SUM(CASE WHEN storeID = 'MAD' THEN stock ELSE 0 END) AS stockMAD从股票按产品 ID、尺寸分组

I'm creating an SQL statement that will return a list of products and the quantity of each one of them I can find in every store.

The structure of my table (with some sample data) is as follows:

productID - size - color - stock - storeID  
1         - S    - RED01 - 1     - BCN   
1         - S    - RED01 - 3     - MAD   
2         - S    - YEL02 - 0     - BCN   
2         - S    - YEL02 - 2     - MAD   
1         - S    - RED01 - 1     - BCN2  

I need a result similar to this one:

productID - size - stockBCN (BCN + BCN2) - stockMAD  
1         - S    - 2                     - 3  
2         - S    - 0                     - 2

I'm using this statement, and works fine just for an unique product

SELECT DISTINCT prodID, size,
    (SELECT SUM(stock) FROM stocks WHERE storeID IN ('BCN','BCN2') AND prodID = 1 AND size = 'S' AND color = 'RED01' GROUP BY prodID, size, color) AS stockBCN,
    (SELECT SUM(stock) FROM stocks WHERE storeID = 'MAD' AND prodID = 1 AND size = 'S' AND color = 'RED01' GROUP BY prodID, size, color) AS stockMAD,
FROM stocks WHERE storeID IN ('BCN','BCN2','MAD')
AND prodID = (1) AND size = 'S' AND color = 'RED01'

How can I change it to make it work for all the rows in the table?

You probably want to leverage the GROUP BY clause instead of going with DISTINCT there, i.e.:

SELECT productId, Size,
SUM(CASE WHEN storeID IN ('BCN', 'BCN2') THEN stock ELSE 0 END) AS stockBCN,
SUM(CASE WHEN storeID = 'MAD' THEN stock ELSE 0 END) AS stockMAD
FROM stocks
GROUP BY productId, Size