我们有一个扩展方法做的正是这 MoreLINQ 。你可以看一下那里的实施，但基本上它是通过数据迭代，记住到目前为止，我们所见到的最大的元素，并将其投射下产生的最大值的情况。

We have an extension method to do exactly this in MoreLINQ. You can look at the implementation there, but basically it's a case of iterating through the data, remembering the maximum element we've seen so far and the maximum value it produced under the projection.

在你的情况，你会做这样的事情：

In your case you'd do something like:

var item = items.MaxBy(x => x.Height);

这是比任何这里psented以外迈赫达德的第二个解决方案解决方案$ P $的更好（IMO）（这基本上是一样的 MaxBy ）：

This is better (IMO) than any of the solutions presented here other than Mehrdad's second solution (which is basically the same as MaxBy):

• 这是为O（n），不像上发现每次迭代的最大值 previous接受的答案（使它为O（n ^ 2））


• 排序的解决方案是O（n log n）的


• 服用最高值，然后找到与该值的第一个元素是O（n），但遍历序列的两倍。如果可能的话，你应该在单通方式使用LINQ。


• 这是一个简单得多阅读和理解比骨料的版本，每个单元仅计算投影一次

• It's O(n) unlike the previous accepted answer which finds the maximum value on every iteration (making it O(n^2))
• The ordering solution is O(n log n)
• Taking the Max value and then finding the first element with that value is O(n), but iterates over the sequence twice. Where possible, you should use LINQ in a single-pass fashion.
• It's a lot simpler to read and understand than the aggregate version, and only evaluates the projection once per element