更新时间:2023-01-22 20:30:51
只需替换您的RegEx规则[AZ] + with。* [AZ] +。*(以及其他RegEx规则)
Simply replace your RegEx rule [A-Z]+ with .*[A-Z]+.* (and other RegEx rules as well)
规则
[AZ] +仅匹配所有字符大写的字符串
[A-Z]+ matches only strings with all characters capitalized
示例:AVATAR,AVA,TAR,AAAAAA
无效:AVATAr
。*匹配所有字符串(0+个字符)
.* matches all strings (0+ characters)
示例:1,2,AVATAR,AVA ,TAR,a,b,c
。* [AZ] +。*匹配所有至少有一个资本的字符串信
.*[A-Z]+.* matches all strings with at least one capital letter
示例:Avatar,avataR,aVatar
说明:
我。 。*将尝试匹配0或更多的任何东西
II。 [A-Z] +将需要至少一个大写字母(因为+)
III。 。*将尝试匹配0或更多的任何东西
I. .* will try to match 0 or more of anything
II. [A-Z]+ will require at least one capital letter (because of the +)
III. .* will try to match 0 or more of anything
Avatar [empty | A| vatar]
aVatar [a| V| atar]
aVAtar [a| VA| tar]
Avatar [empty | "A" | "vatar"]
aVatar ["a" | "V" | "atar"]
aVAtar ["a" | "VA" | "tar"]
工作代码
func checkTextSufficientComplexity(var text : String) -> Bool{
let capitalLetterRegEx = ".*[A-Z]+.*"
var texttest = NSPredicate(format:"SELF MATCHES %@", capitalLetterRegEx)
var capitalresult = texttest!.evaluateWithObject(text)
println("\(capitalresult)")
let numberRegEx = ".*[0-9]+.*"
var texttest1 = NSPredicate(format:"SELF MATCHES %@", numberRegEx)
var numberresult = texttest1!.evaluateWithObject(text)
println("\(numberresult)")
let specialCharacterRegEx = ".*[!&^%$#@()/]+.*"
var texttest2 = NSPredicate(format:"SELF MATCHES %@", specialCharacterRegEx)
var specialresult = texttest2!.evaluateWithObject(text)
println("\(specialresult)")
return capitalresult || numberresult || specialresult
}
示例:
checkTextSufficientComplexity("Avatar") // true || false || false
checkTextSufficientComplexity("avatar") // false || false || false
checkTextSufficientComplexity("avatar1") // false || true || false
checkTextSufficientComplexity("avatar!") // false || false || true