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分享程序员开发的那些事...
且构网 - 分享程序员编程开发的那些事

合并具有不同列的查询

更新时间:2023-01-27 07:46:26

设置多余的未使用列为空的列

Set up extra columns that are null where they are not used

SELECT distinct 
         DP.DIM_PROJECT_ID, 
         DP.PROJECT_NAME,
         DP.PROJECT_TITLE,
         null as admin, 
         DP.POINT_OF_CONTACT,
         DP.FIELD,
         DD.YEAR

  FROM   FACT_Table   FAT 
  RIGHT OUTER 
  JOIN   DIM_A        DA    on FAT.DIM_A_ID = DA.DIM_A_ID 
  JOIN   DIM_P        DP    on DA.DIM_P_ID = DP.DIM_P_ID
  JOIN   BRIDGE_USER  BUP   on BUP.BRIDGE_ID = DP.DIM_P_ID
            JOIN DIM_DATE     DD    on DD.DATE_KEY = DA.A_START_DATE_ID
  WHERE DA.AWARD_CATEGORY <> 'N/A'   
    and DD.YEAR = '2013'
    and NOT EXISTS (
                     SELECT *
                       FROM BRIDGE_USER  BUP_INNER 
                       JOIN DIM_P        DP_INNER
                          on DP_INNER.DIM_P_ID = BUP_INNER.DIM_P_ID
                       WHERE DP_INNER.DIM_P_ID = DP.DIM_P_ID
                         AND BUP_INNER.ADMIN_FLAG = 'Y'
                   ) 
UNION ALL

SELECT distinct
    DP.DIM_PROJECT_ID,
    DP.PROJECT_NAME,
    DP.PROJECT_TITLE,
    DU.NAME_LAST CONCAT ', ' CONCAT t1.NAME_FIRST AS ADMIN,
    null as POINT_OF_CONTACT,
    DD.YEAR,
    DP.FIELD
  FROM FACT_Table as FAT
  JOIN DIM_P         DP   ON  FAT.DIM_P_ID = DP.DIM_P_ID
  JOIN BRIDGE_USER   BUP  on  BUP.DIM_P_ID = DP.DIM_P_ID
                          and BUP.ADMIN_FLAG = 'Y'
  JOIN DIM_USER      DU   ON  FAT.DIM_USER_ID = DU.DIM_USER_ID
  JOIN DIM_DATE      DD   on  DD.DATE_KEY = DA.A_START_DATE_ID
                          and DD.YEAR = '2013'
  JOIN DIM_A         DA   ON  DA.DIM_A_ID = FAT.DIM_A_ID
                          and DA.AWARD_CATEGORY <> 'NA'

NOT EXISTS应该更有效,因为一旦找到满足子查询的一行,它将返回一个答案.另一方面,COUNT(*)将继续搜索满足子查询的所有所有行.

NOT EXISTS should be more efficient since it will return an answer the moment one row is found satisfying the subquery. COUNT(*) on the other hand, will continue searching for all rows that satisfy the subquery.

我之所以省略了GROUP BY子句,是因为不涉及聚合函数,因此我不理解您要使用它们做什么.

I left out your GROUP BY clauses because I did not understand what you were trying to do with them since there are no aggregate functions involved.