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MYSQL 查询以获取日期差异

更新时间:2023-01-27 17:31:19

首先感谢大家的帮助

这是返回确切结果的查询

Here is the query which return exact result

select p_id,ag_id,
     p_abb,ag_name
    ,sum(-1.00 * miles * price - coalesce(fees,0) - coalesce(cost,0)) as profit
    ,sum(miles) 'Total Miles',avg(price / miles) 'Average'
    ,DATEDIFF(min(buy_dt),min(sell_dt)) as 'Days'
     From
     (
         SELECT p.id 'p_id',ag.id 'ag_id',p.abbreviation 'p_abb',ag.name 'ag_name'
         ,miles
         ,price
         ,fees
         ,c.cost
         ,case when t.trans_type ='Sell' then transaction_date end 'sell_dt'
         ,case when t.trans_type ='Buy' then transaction_date end 'buy_dt'
         ,transaction_date
       FROM transactions t
       inner join accounts a on t.account_id = a.id
       inner join programs p on a.program_id = p.id
       inner join agents ag on t.agent_id = ag.id
       LEFT JOIN (
            SELECT rp.sell_id, sum(rp.miles * t.price) as cost
           from report_profit rp
           inner join transactions t on rp.buy_id = t.id
           where t.miles > 50000
           group by rp.sell_id
           order by rp.sell_id
          ) c on t.id = c.sell_id

  ) t1
  group by p_id, ag_id

再次感谢大家..