更新时间:2023-01-30 13:41:32
这是我的操作方式。
我创建了另一个 ArrayList< Integer>
和2个 List< Array>
,最后它们是变量:
I created another ArrayList<Integer>
and 2 List<Array>
, at the end they were the "variables:
private ArrayList<Integer> drawables, mFiltered;
private String[] brands;
private List<String> stringList, mFilteredNames;
int resId;
然后在启动适配器时,我
Then when "starting" the adapter, I sorted the string array this way:
stringList = new ArrayList<String>(Arrays.asList(brands));
Collections.sort(stringList);
loadLogo(stringList);
新的loadLogo无效是:
The new loadLogo void is:
private void loadLogo(List<String> list) {
drawables = new ArrayList<>();
for (String extra : list) {
int res = r.getIdentifier(extra, "drawable", p);
if (res != 0) {
final int brandInt = r.getIdentifier(extra, "drawable", p);
if (brandInt != 0)
drawables.add(brandInt);
}
}
}
这是我的过滤功能:
public synchronized void filter(CharSequence s) {
if (s == null || s.toString().trim().isEmpty()) {
if (mFiltered != null) {
mFiltered = null;
notifyDataSetChanged();
}
} else {
if (mFiltered != null)
mFiltered.clear();
mFiltered = new ArrayList<>();
mFilteredNames = new ArrayList<String>();
for (int i = 0; i < stringList.size(); i++) {
final String name = stringList.get(i);
if (name.toLowerCase(Locale.getDefault())
.startsWith(s.toString().toLowerCase(Locale.getDefault()))) {
mFiltered.add(drawables.get(i));
mFilteredNames.add(name);
}
}
notifyDataSetChanged();
}
并在 onBindViewHolder
中 RecyclerView
适配器的方法,我这样写:
And in the onBindViewHolder
method of the RecyclerView
adapter, I wrote this:
if (mFiltered != null) {
resId = mFiltered.get(position);
holder.logo.setImageResource(resId);
} else {
resId = drawables.get(position);
holder.logo.setImageResource(resId);
}
我不知道这是否是正确的方法为我的目的而努力。如果有人有更好的答案,我将不胜感激。
I don't know if it's the right way to do it, but is working for my purpose. If someone has a better answer I will be thankful.
此外,我不知道这对其他人有多大用处,因为它主要用于自定义目的,但我希望这对其他人也有帮助。
Also, I don't know how useful this could be for other people as it is mostly for a custom purpose, but I hope this helps someone else too.