更新时间:2022-01-18 04:01:34
按照以下步骤获得正确的结果:
Follow these steps for a correct result:
try {
SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss.SSS");
Date parsedDate = dateFormat.parse(yourString);
Timestamp timestamp = new java.sql.Timestamp(parsedDate.getTime());
} catch(Exception e) { //this generic but you can control another types of exception
// look the origin of excption
}
请注意.parse(String)
可能会抛出 ParseException
.