更新时间:2023-02-03 08:29:25
boost :: lexical_cast 。如果无法完成转换,则会抛出异常。
Use boost::lexical_cast. If the cast cannot be done, it will throw an exception.
#include <boost/lexical_cast.hpp>
#include <iostream>
#include <string>
int main(void)
{
std::string s;
std::cin >> s;
try
{
int i = boost::lexical_cast<int>(s);
/* ... */
}
catch(...)
{
/* ... */
}
}
没有提升:
#include <iostream>
#include <sstream>
#include <string>
int main(void)
{
std::string s;
std::cin >> s;
try
{
std::stringstream ss(s);
int i;
if ((ss >> i).fail() || !(ss >> std::ws).eof())
{
throw std::bad_cast();
}
/* ... */
}
catch(...)
{
/* ... */
}
}
伪造提升:
#include <iostream>
#include <sstream>
#include <string>
template <typename T>
T lexical_cast(const std::string& s)
{
std::stringstream ss(s);
T result;
if ((ss >> result).fail() || !(ss >> std::ws).eof())
{
throw std::bad_cast();
}
return result;
}
int main(void)
{
std::string s;
std::cin >> s;
try
{
int i = lexical_cast<int>(s);
/* ... */
}
catch(...)
{
/* ... */
}
}
如果你想要这些函数的no-throw版本,你必须捕获适当的异常(我不认为 boost :: lexical_cast
-throw version),类似这样的:
If you want no-throw versions of these functions, you'll have to catch the appropriate exceptions (I don't think boost::lexical_cast
provides a no-throw version), something like this:
#include <iostream>
#include <sstream>
#include <string>
template <typename T>
T lexical_cast(const std::string& s)
{
std::stringstream ss(s);
T result;
if ((ss >> result).fail() || !(ss >> std::ws).eof())
{
throw std::bad_cast();
}
return result;
}
template <typename T>
bool lexical_cast(const std::string& s, T& t)
{
try
{
// code-reuse! you could wrap
// boost::lexical_cast up like
// this as well
t = lexical_cast<T>(s);
return true;
}
catch (const std::bad_cast& e)
{
return false;
}
}
int main(void)
{
std::string s;
std::cin >> s;
int i;
if (!lexical_cast(s, i))
{
std::cout << "Bad cast." << std::endl;
}
}