一个查询就搞定的方法:

The way to do it in one query:

SELECT COUNT(my_table.id) AS total,
 CONCAT(YEAR(dates.ddate), '-', MONTH(dates.ddate),  '-', DAY(dates.ddate))
FROM (
   -- Creates "on the fly" 65536 days beginning from 2000-01-01 (179 years)
   SELECT DATE_ADD("2000-01-01", INTERVAL (b1.b + b2.b + b3.b + b4.b + b5.b + b6.b + b7.b + b8.b + b9.b + b10.b + b11.b + b12.b + b13.b + b14.b + b15.b + b16.b) DAY) AS ddate FROM
   (SELECT 0 AS b UNION SELECT 1) b1,
   (SELECT 0 AS b UNION SELECT 2) b2,
   (SELECT 0 AS b UNION SELECT 4) b3,
   (SELECT 0 AS b UNION SELECT 8) b4,
   (SELECT 0 AS b UNION SELECT 16) b5,
   (SELECT 0 AS b UNION SELECT 32) b6,
   (SELECT 0 AS b UNION SELECT 64) b7,
   (SELECT 0 AS b UNION SELECT 128) b8,
   (SELECT 0 AS b UNION SELECT 256) b9,
   (SELECT 0 AS b UNION SELECT 512) b10,
   (SELECT 0 AS b UNION SELECT 1024) b11,
   (SELECT 0 AS b UNION SELECT 2048) b12,
   (SELECT 0 AS b UNION SELECT 4096) b13,
   (SELECT 0 AS b UNION SELECT 8192) b14,
   (SELECT 0 AS b UNION SELECT 16384) b15,
   (SELECT 0 AS b UNION SELECT 32768) b16
 ) dates
 LEFT JOIN my_table ON dates.ddate = my_table.created_at
 GROUP BY dates.ddate
 ORDER BY dates.ddate

仅当您要测试并且问题中没有指示my_table"时才需要下一个代码:

The next code is only necessary if you want to test and don't have the "my_table" indicated on the question:

create table `my_table` (
    `id` int (11),
    `created_at` date 
); 
insert into `my_table` (`id`, `created_at`) values('1','2000-01-01');
insert into `my_table` (`id`, `created_at`) values('2','2000-01-01');
insert into `my_table` (`id`, `created_at`) values('3','2000-01-01');
insert into `my_table` (`id`, `created_at`) values('4','2001-01-01');
insert into `my_table` (`id`, `created_at`) values('5','2100-06-06');