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Laravel在单个子句中使用多个where和sum

更新时间:2023-02-04 23:18:41

另一种获取不同类型操作的条件和的方法,您可以在InstagramAccount模型中定义hasOne()关系,例如

Another approach to get conditional sum for your different types of action, you can define a hasOne() relation in your InstagramAccount model like

public function history_sum()
{
    return $this->hasOne(InstagramActionsHistory::class, 'account_id')
        ->select('account_id',
            DB::raw('sum(case when action_type = 1 then 0 END) as `like`'),
            DB::raw('sum(case when action_type = 2 then 0 END) as `follow`'),
            DB::raw('sum(case when action_type = 3 then 0 END) as `followBack`')
        )->groupBy('account_id');
}

那么您可以急于将相关数据加载为

Then you can eager load the related data as

$userAddedPagesList = auth()->user()->instagramPages()->with('history_sum')->get();

使用此方法将仅执行一个额外的查询,以根据您的条件获得3个不同的总和结果

Going through with this approach will execute only one extra query to get 3 different sum results based on your criteria

select `account_id`,
sum(case when action_type = 1 then action_type else 0 END) as `like`, 
sum(case when action_type = 2 then action_type else 0 END) as `follow`, 
sum(case when action_type = 3 then action_type else 0 END) as `followBack` 
from `instagram_actions_histories` 
where `instagram_actions_histories`.`account_id` in (?, ?, ?) 
group by `account_id`

尽管与使用withCount的其他方法相比(这也是一个有效的答案),将为每种操作类型添加3个相关的相关子查询,这可能会导致性能开销,但生成的查询如下所示

While as compare to other approach (which is a valid answer also) using withCount will add 3 dependent correlated sub queries for each action type which may result as a performance overhead, generated query will look something like below

select `instagram_account`.*, 
(select sum(action_type) from `instagram_actions_histories` where `instagram_account`.`id` = `instagram_actions_histories`.`account_id` and `action_type` = ?) as `like`, 
(select sum(action_type) from `instagram_actions_histories` where `instagram_account`.`id` = `instagram_actions_histories`.`account_id` and `action_type` = ?) as `follow`,
(select sum(action_type) from `instagram_actions_histories` where `instagram_account`.`id` = `instagram_actions_histories`.`account_id` and `action_type` = ?) as `followBack`
from `instagram_account` 
where `instagram_account`.`user_id` = ? 
and `instagram_account`.`user_id` is not null

要检查生成的查询,请参考 Laravel 5.3-如何在页面上记录所有查询?

To check the generated queries refer to Laravel 5.3 - How to log all queries on a page?