Copying my own answer from 如何将 Node.js 应用程序作为自己的进程运行?

Copying my own answer from How do I run a Node.js application as its own process?

2015 年回答:几乎每个 Linux 发行版都带有 systemd，这意味着永远不再需要 monit、PM2 等 - 您的操作系统已经处理了这些任务.

2015 answer: nearly every Linux distro comes with systemd, which means forever, monit, PM2, etc are no longer necessary - your OS already handles these tasks.

制作一个 myapp.service 文件(显然，用您的应用程序名称替换myapp"):

Make a myapp.service file (replacing 'myapp' with your app's name, obviously):

[Unit]
Description=My app

[Service]
ExecStart=/var/www/myapp/app.js
Restart=always
User=nobody
# Note Debian/Ubuntu uses 'nogroup', RHEL/Fedora uses 'nobody'
Group=nogroup
Environment=PATH=/usr/bin:/usr/local/bin
Environment=NODE_ENV=production
WorkingDirectory=/var/www/myapp

[Install]
WantedBy=multi-user.target

请注意，如果您是 Unix 新手: /var/www/myapp/app.js 应该有 #!/usr/bin/env 节点 在第一行并打开可执行模式chmod +x myapp.js.

Note if you're new to Unix: /var/www/myapp/app.js should have #!/usr/bin/env node on the very first line and have the executable mode turned on chmod +x myapp.js.

将您的服务文件复制到/etc/systemd/system.

Copy your service file into the /etc/systemd/system.

使用 systemctl start myapp 启动它.

使用 systemctl enable myapp 使其在启动时运行.

Enable it to run on boot with systemctl enable myapp.

使用 journalctl -u myapp

这取自 我们如何在 Linux 上部署节点应用程序，2018 版，其中还包括生成 AWS/DigitalOcean/Azure CloudConfig 以构建 Linux/节点服务器的命令(包括 .service 文件).