使用AChampion建议的正则表达式，您可以执行以下操作.

Using the regular expressions as suggested by AChampion, you can do the following.

string = "44-23+44*4522"
import re
result = re.findall(r'\d+',string)

r''表示原始文本，'\ d'表示十进制字符，而+表示1次或多次.如果您希望字符串中的浮点数不希望被分开，则可以使用句号."括起来.

The r'' signifies raw text, the '\d' find a decimal character and the + signifies 1 or more occurrences. If you expect floating points in your string that you don't want to be separated, you might what to bracket with a period '.'.

re.findall(r'[\d\.]+',string)