我猜想您要将那组数字作为字符串传递，并拆分成单独的数字.这比您想像的要难，因为Oracle没有附带内置的令牌生成器.奇怪吧?

I am guessing you want to pass that set of numbers as a string and split into into individual numbers. This is harder than you might think, because Oracle doesn't come with a built-in tokenizer. Weird, huh?

有许多PL/SQL标记生成器解决方案可以解决Das Interwabs的问题.我使用的是 Anup Pani的实现的变体，它使用Regex(因此仅Oracle 10g或更高版本).我的变体返回一个数字数组，我已将其声明为SQL类型:

There are a number of PL/SQL tokenizer solutions knocking around Das Interwabs. I am using a variant of Anup Pani's implementation, which uses Regex (hence only Oracle 10g or higher). My variant returns an array of numbers which I have declared as a SQL type:

SQL> create or replace type numbers as table of number
  2  /

Type created.

SQL>

这意味着我可以将其用作SELECT语句中TABLE()函数的输入:

This means I can use it as an input to a TABLE() function in a SELECT statement:

SQL> select * from table (str_to_number_tokens('20000, 240004, 375000, 255000'))
  2  /

COLUMN_VALUE
------------
       20000
      240004
      375000
      255000

SQL>

这意味着我可以将您的数字字符串转换成可以在查询中加入的表，如下所示:

This means I can turn your string of numbers into a table which I can join to in a query, like this:

SQL> select val
  2  from t23
  3       , ( select column_value as i_no
  4           from table (str_to_number_tokens('20000, 240004, 375000, 255000')) ) sq
  5  where t23.year = 2010
  6  and   sq.i_no between t23.r_min and t23.r_max
  7  order by t23.priority
  8  /

       VAL
----------
        82
        50
        52

SQL>