是！

string url = Url.Action(MVC.Views.Index());

例如

..您应该获得与视图中相同的对象集，只需访问MVC对象并将其传递给Url.Action().

.. for example. You should get the same set of objects you get in your views, just access the MVC object and pass it to Url.Action().

有关在控制器操作中使用T4MVC的更多说明，请参见:

Some more notes about using T4MVC in a controller action here: http://www.davidferguson.me.uk/Blogs/Post/strongly-typed-actions-views-and-controllers-with-t4mvc