假设 Python 将名称视为普通字符串，您首先必须将其解码为 un​​icode:

>>>名称'克里斯滕森 SK\xf6ld'>>>unicode(名称，'latin-1')u'Christensen Sk\xf6ld'

实现此目的的另一种方法:

>>>name.decode('latin-1')u'Christensen Sk\xf6ld'

注意字符串前面的u"，表示它是未编码的.如果你打印这个，带重音的字母会正确显示:

>>>打印 name.decode('latin-1')克里斯滕森·斯科尔德

顺便说一句:必要时，您可以使用 de "encode" 方法将 unicode 转换为例如一个 UTF-8 字符串:

>>>name.decode('latin-1').encode('utf-8')'克里斯滕森 Sk\xc3\xb6ld'

When I tried to get the content of a tag using "unicode(head.contents[3])" i get the output similar to this: "Christensen Sk\xf6ld". I want the escape sequence to be returned as string. How to do it in python?

Assuming Python sees the name as a normal string, you'll first have to decode it to unicode:

>>> name
'Christensen Sk\xf6ld'
>>> unicode(name, 'latin-1')
u'Christensen Sk\xf6ld'

Another way of achieving this:

>>> name.decode('latin-1')
u'Christensen Sk\xf6ld'

Note the "u" in front of the string, signalling it is uncode. If you print this, the accented letter is shown properly:

>>> print name.decode('latin-1')
Christensen Sköld

BTW: when necessary, you can use de "encode" method to turn the unicode into e.g. a UTF-8 string:

>>> name.decode('latin-1').encode('utf-8')
'Christensen Sk\xc3\xb6ld'