这可以通过使用 using 将名称拉入当前范围来修改:

This can be amended by pulling the names into the current scope using using:

template<typename T> struct Subclass : public Superclass<T> {
  using Superclass<T>::b;
  using Superclass<T>::g;

  void f() {
    g();
    b = 3;
  }
};

或者通过this指针访问来限定名称:

Or by qualifying the name via the this pointer access:

template<typename T> struct Subclass : public Superclass<T> {
  void f() {
    this->g();
    this->b = 3;
  }
};

或者，正如您已经注意到的，通过限定全名.

Or, as you’ve already noticed, by qualifying the full name.

之所以有必要这样做，是因为 C++ 不考虑用于名称解析的超类模板(因为它们是从属名称并且不考虑从属名称).它在您使用 Superclass 时有效，因为它不是模板(它是模板的实例化)，因此它的嵌套名称不依赖 名字.

The reason why this is necessary is that C++ doesn’t consider superclass templates for name resolution (because then they are dependent names and dependent names are not considered). It works when you use Superclass<int> because that’s not a template (it’s an instantiation of a template) and thus its nested names are not dependent names.