如果你想要一个通用的转换器功能，这应该有效：

If you want a generic converter function, this should work:

function globStringToRegex(str) {
    return new RegExp(preg_quote(str).replace(/\\\*/g, '.*').replace(/\\\?/g, '.'), 'g');
}
function preg_quote (str, delimiter) {
    // http://kevin.vanzonneveld.net
    // +   original by: booeyOH
    // +   improved by: Ates Goral (http://magnetiq.com)
    // +   improved by: Kevin van Zonneveld (http://kevin.vanzonneveld.net)
    // +   bugfixed by: Onno Marsman
    // +   improved by: Brett Zamir (http://brett-zamir.me)
    // *     example 1: preg_quote("$40");
    // *     returns 1: '\$40'
    // *     example 2: preg_quote("*RRRING* Hello?");
    // *     returns 2: '\*RRRING\* Hello\?'
    // *     example 3: preg_quote("\\.+*?[^]$(){}=!<>|:");
    // *     returns 3: '\\\.\+\*\?\[\^\]\$\(\)\{\}\=\!\<\>\|\:'
    return (str + '').replace(new RegExp('[.\\\\+*?\\[\\^\\]$(){}=!<>|:\\' + (delimiter || '') + '-]', 'g'), '\\$&');
}

（preg_quote函数来自： http://phpjs.org/functions/preg_quote/ ）。

(preg_quote function from here: http://phpjs.org/functions/preg_quote/).

使用：

var realRegex = globStringToRegex("2012-*-*.js"); //returns a RegExp object of /2012\-.*\-.*\.js/g

这是一个工作的JS小提琴：

Here's a JS fiddle of it working:

http：// jsfiddle.net/d5sdw/2/

然后您可以使用RegExp对象进行匹配：

You can then use the RegExp object to match:

if (yourString.match(realRegex)) { //do something

更新：支持单个通配符的？。

Update: Supports ? for single wildcard character.

基本上全部这样做是将整个字符串转换为非正则表达式，然后确保 * 映射到。* 和？被映射到。，因为它们是等效的。

Basically all this does is convert the whole string to non regex, and then makes sure that * gets mapped to .* and ? gets mapped to ., as they're the equivalent.